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In case of vernier callipers, each cm on the main scale is divided into 10 equal parts. If 5th vernier scale division coincides with nineth main scale division. Find the value of vernier constant

Option: 1

0.01 cm


Option: 2

0.02 cm


Option: 3

0.03 cm


Option: 4

0.04 cm


Answers (1)

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\text { 1 M.S.D }=\frac{1}{10} \mathrm{~cm}\\\\ Now, 10 \mathrm{VSD}=9 \mathrm{MSD}\\\\ 1 V S D=\frac{9}{10} M S D\\\ \text {So, Vernier constant = least count}\\\ \begin{aligned} & =1 \text { M.S.D - 1 V.S.D } \\ & =\frac{1}{10} M \cdot \mathrm{S} \cdot D \\ & =\frac{1}{10} \times \frac{1}{10}=0.01 \mathrm{~cm} \end{aligned}

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Anam Khan

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