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In how many ways 18 different students can be divided into three groups in such a way that they get four, five and nine students?

Option: 1

174053800


Option: 2

6126122


Option: 3

174053840


Option: 4

6126120


Answers (1)

best_answer

Number of ways of dividing (m+n+p) (where \, \, m \neq n \neq p ) things into three unequal
=\frac{(m+n+p) !}{m ! n ! p !}
groups of size m, n, p is
Here m=4, n=5, p=9
Then, the total number of ways:
\frac{18 !}{4 ! 5 ! 9 !}=6126120

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