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In how many ways 12 boys can be divided into 2 teams such that all contains 6 boys to each.

Option: 1

462


Option: 2

924


Option: 3

245


Option: 4

955


Answers (1)

best_answer

The given information is:

Number of boys =12

Number of teams =2

Number of boys to each team =6

Pick first 6 boys from 12 boys, 

Total no. of ways of choosing is:

\frac{12 !}{(12-6) ! 6 !}=\frac{12 !}{6 ! 6 !}=924

Pick last 6 boys from 6 boys and the number of ways this can be done is 1 .

Since the two groups are similar, there is no differentiation between them. Therefore, we need to divide it with 2 !=2 .

The total numbers of ways:

\frac{924}{2}=462

Posted by

avinash.dongre

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