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  • In how many ways can 12 coins be divided into 3 groups in such a way that they get two, three and seven coins?Option: 1 <img alt="7920" src

In how many ways can 12 coins be divided into 3 groups in such a way that they get two, three and seven coins?

Option: 1

7920


Option: 2

60060


Option: 3

7940


Option: 4

60040


Answers (1)

best_answer

Number of ways of dividing (m+n+p) \text { (where } m \neq n \neq p) things into three unequal groups of size m,n,p is =\frac{(m+n+p) !}{m ! n ! p !}

Here m=2, n=3, p=7

Then, the total number of ways: 

\frac{12 !}{2 ! 3 ! 7 !}=7920

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