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  • In how many ways can 16 roads be divided into 3 groups in such a way that they get two, five and nine roads?Option: 1 <img alt="240240" src

In how many ways can 16 roads be divided into 3 groups in such a way that they get two, five and nine roads?

Option: 1

240240


Option: 2

960960


Option: 3

240260


Option: 4

102900


Answers (1)

best_answer

Number of ways of dividing (m+n+p) \text { (where } m \neq n \neq p \text ) things into three unequal

groups of size m,n,p is =\frac{(m+n+p) !}{m ! n ! p !}

Here m=2, n=5, p=9

Then, the total number of ways:

\frac{16 !}{2 ! 5 ! 9 !}=240240

Posted by

Rakesh

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