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In how many ways can 20 kids be divided into 3 groups in such a way that they get four, six and ten kids?

Option: 1

38798760


Option: 2

239028075


Option: 3

2549632800


Option: 4

2920488480


Answers (1)

best_answer

Number of ways of dividing \left.(m+n+p)(where \, \, m \neq n \neq p\right) things into three unequal

groups of size m,n,p is =\frac{(m+n+p) !}{m ! n ! p !}

Here m=4, n=6, p=10

Then, the total number of ways: 

\frac{20 !}{4 ! 6 ! 10 !}=38798760

Posted by

SANGALDEEP SINGH

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