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  • In how many ways can 26 members of a gang be divided into 3 groups in such a way that they get four, seven and fifteen members?Option: 1 <i

In how many ways can 26 members of a gang be divided into 3 groups in such a way that they get four, seven and fifteen members?

Option: 1

2920488440


Option: 2

239028075


Option: 3

2549632800


Option: 4

2920488480


Answers (1)

best_answer

Number of ways of dividing (m+n+p) \text { (where } m \neq n \neq p)  things into three unequal

groups of size m,n,p is =\frac{(m+n+p) !}{m ! n ! p !}

Here m=4, n=7, p=15

Then, the total number of ways: 

\frac{26 !}{4 ! 7 ! 15 !}=2549632800

Posted by

Anam Khan

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