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  • In how many ways can 28 boys be divided into 3 groups in such a way that they get two, eleven and fifteen boys?Option: 1 <img alt="29204884

In how many ways can 28 boys be divided into 3 groups in such a way that they get two, eleven and fifteen boys?

Option: 1

2920488440


Option: 2

174053880


Option: 3

174053840


Option: 4

2920488480


Answers (1)

best_answer

Number of ways of dividing (m+n+p) \text { (where } m \neq n \neq p \text ) things into three unequal

groups of size m,n,p is =\frac{(m+n+p) !}{m ! n ! p !}

Here  m=2, n=11, p=15

Then, the total number of ways: 

\frac{28 !}{2 ! 11 ! 15 !}=2920488480

Posted by

Rishi

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