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In how many ways can 8 different objects be distributed in 3 persons in such a way that they get one, three and four objects?

Option: 1

120


Option: 2

128


Option: 3

280


Option: 4

252


Answers (1)

best_answer

Number of ways of dividing (m+n+p)$ (where $m \neq n \neq p) things into three unequal groups of size \mathrm{m}, \mathrm{n}, \, \mathrm{p} \, \, is =\frac{(m+n+p) !}{m ! n ! p !}
Here m=1, n=3, p=4
Then, the total number of ways:
\frac{8 !}{1 ! 3 ! 4 !}=280

Posted by

HARSH KANKARIA

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