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  • In how many ways can we distribute 6 distinct balls among 3 children such that each one gets at least 2 balls?Option: 1 90<div class='q

In how many ways can we distribute 6 distinct balls among 3 children such that each one gets at least 2 balls?

Option: 1

90


Option: 2

60


Option: 3

 180


Option: 4

790


Answers (1)

best_answer

Number of ways to select 2 balls out of 6 is \mathrm{6 c_{2}}

Remaining 4 balls, ways to select 2 out of 4 is \mathrm{4 c_{2}}

Now 2 balls remained, third person gets 2 balls in \mathrm{2 c_{2}}

Total possible ways so that each one gets at least 2 balls is,

\mathrm{\frac{6 !}{4 ! 2 !} \times \frac{4 !}{2 ! 2 !} \times 2 c_{2}=90}

Total number of ways: 90

Posted by

Suraj Bhandari

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