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In how ways 5 toys are distributed among three children, such that each gets at least one toy.

 

Option: 1

120


Option: 2

150


Option: 3

180


Option: 4

200


Answers (1)

best_answer

The possibilities of distributing 3 toys are 1, 1, 3 or 2, 2, 1.

The total number of ways is given by,

\frac{5!}{\left ( 1! \right )^{2}\times3!\times2!}\times3!+\frac{5!\times3!}{\left ( 2! \right )^{2}\times1!\times2!}

\frac{120}{2}+\frac{120\times6}{8}=150

Therefore, the total number of ways is 150 ways.

 

Posted by

Rishabh

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