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In Interference between two light waves of intensity I1 & I2, the ratio of maximum and minimum intensity in Interference pattern is 16 : 1. Determine the ratio I1 : I2 (1)  23/9 (2) 24/7 (3)25/9 (4) 16/9

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Resultant Intensity of two wave

I= I_{1}+I_{2}+2\sqrt{I_{1}I_{2}}\cos \theta

where 

I_{1}= Intencity of wave 1

I_{2}= Intencity of wave 2

\theta = Phase difference

So I_{max }= \left ( \sqrt{I_{1}}+\sqrt{I_{2}} \right )^{2}

and I_{min }= \left ( \sqrt{I_{1}}-\sqrt{I_{2}} \right )^{2}

use these formulaes and solve it

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avinash.dongre

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