Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

In LC circuit the inductanceL=40\; mH and capacitance C=100\; \mu F. If a voltage V(t)=10\sin (314)t) is applied to the circuit , the current in the circuit is given as :
Option: 1 10\cos 314\; t      
Option: 2 0.52\cos 314\; t      
Option: 3 5.2\cos 314\; t      
Option: 4 0.52\; \sin 314\; t      
 

Answers (1)

best_answer

As Z=\sqrt{R^{2}+\left ( X_{C}-X_{L} \right )^{2}}

But R=0

 Z=(X_{C}-X_{L})=\frac{1}{C_{w}}-Lw                                                   

 \Rightarrow Z=\frac{1}{100\ast 10^{-4}\ast 314}-(314\ast 40\ast 10^{-3})=31.84-12.56=19.28\Omega

i=\frac{V_{0}}{Z}\sin \left ( 314t+\frac{\pi }{2} \right )=\frac{10}{19.28}\cos (314t)=0.52\cos (314t)

Hence the correct option is (2).

Posted by

avinash.dongre

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

Engineering aspirant dies by suicide in Kota, fourth case this year
anam-khan

What is non-Aadhaar declaration in JEE Main 2025? Explain mismatch between image, face
anam-khan

Forgot JEE Main password 2025 for downloading admit card? Here’s what to do

Latest Question