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In sulphur estimation, $\mathrm{ 0.471 g}$ of an organic compound gave $\mathrm{1.4439 g}$ of barium sulphate. The percentage of sulphur in the compound is______(Nearest Integer)
(Given: Atomic mass $\mathrm{Ba: 137u, S: 32u, O: 16u}$ )
Option: 1
42

Option: 2
-

Option: 3
-

Option: 4
-

Answers (1)

best_answer

$\mathrm{Organic \: \: compound}$ $\mathrm{ \rightarrow BaSO_{4}}$

$\mathrm{Weight}$ $\mathrm{= 0.417 g}$ $\mathrm{Weight}$ $\mathrm{= 1.44 g}$

$\mathrm{moles }$ $\mathrm{BaSO_{4}=\frac{1.44}{233}=}$ $\mathrm{moles \: of \: Sulphur}$

$\mathrm{Weight \: Sulphur =\frac{1.44}{233}\times 32\: gram}$

$\mathrm{%S=\frac{Weight \: of \: sulphar}{Weight \: of\: organic}\times 100}$

$\mathrm{\Rightarrow \frac{1.44\times 32}{233\times 0.471}\times 100}$

$\mathrm{\Rightarrow \frac{46.08}{109.743}\times 100}$

$\mathrm{\Rightarrow 41.98\simeq 42}$

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