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  • In the above reaction, 3.9 g of benzene on nitration gives 4.92 g of nitrobenzene. The percentage yield of nitrobenzene in the above re

In the above reaction, 3.9 g of benzene on nitration gives 4.92 g of nitrobenzene. The percentage yield of nitrobenzene in the above reaction is ______%. (Round off to the Nearest Integer). (Given atomic mass : C : 12.0 \; u,H: 1.0\; u,O:16.0\; u,N:14.0\; u)
Option: 1 80
Option: 2 -
Option: 3 -
Option: 4 -

Answers (1)

best_answer

Given reaction:

Theoretically calculation:-

So, from 78 g of benzene on nitration gives 123 g of nitrobenzene.

1 g of Benzene on nitration gives 123/78 g of nitrobenzene.

3.9 g of benzene on nitration gives 3.9 x(123/78) g of nitrobenzene.

3.9 g of benzene on nitration gives 6.15 g of nitrobenzene.

But the actual amount of nitrobenzene formed is 4.92 g.

\% \text { yield }=\frac{\text { formed actually }}{\text { formed theoretically }} \times 100

\% \text { yield }=\frac{4.92}{6.15} \times 100=80 \%

Ans = 80

Posted by

Kuldeep Maurya

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