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In the circuit diagram shown in figure given below, the current flowing through resistance  \mathrm{3\Omega\: is\: \frac{x}{3}\: A. } The value of x is _________

 

Option: 1

1


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

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\begin{aligned} & R_{eq}=0.5+1+4.5+\left(\frac{3 \times6}{9}\right) \\ & R_{eq}=6+2=8 \Omega \\ \end{aligned}

\begin{aligned} & \mathrm{I}=\frac{8-4}{8}=\frac{1}{2} \mathrm{~A}=0.5 \mathrm{~A} \\ & \mathrm{I}_1: \mathrm{I}_2=\frac{1}{3}: \frac{1}{6} \\ \end{aligned}

\begin{aligned} & \mathrm{I}_1: \mathrm{I}_2=2: 1 \\ \end{aligned}

\begin{aligned} & \text { and } \mathrm{I}_1+\mathrm{I}_2=0.5 \mathrm{~A} \\ \end{aligned}

\begin{aligned} & \mathrm{I}_1=\frac{2}{3} \times 0.5=\frac{1}{3} \mathrm{~A} \\ & \text { So } \frac{1}{3}=\frac{\mathrm{x}}{3} \Rightarrow \mathrm{x}=1 \end{aligned}

 

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Irshad Anwar

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