Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • In the circuit given <img alt="E=6.0 \mathrm{~V}, R_1=100 \, \, \mathrm{ohms}, R_2=R_3=50 \, \, \mathrm{ohms}, R_4=75 \, \, \mathrm{ohms}" src="https://entrancecorner.oncodecogs.com/gif.latex?E%3D6

In the circuit given E=6.0 \mathrm{~V}, R_1=100 \, \, \mathrm{ohms}, R_2=R_3=50 \, \, \mathrm{ohms}, R_4=75 \, \, \mathrm{ohms}. The equivalent resistance of the circuit, in ohms, is

Option: 1

11.875


Option: 2

26.31


Option: 3

118.75


Option: 4

None of these


Answers (1)

best_answer

In a given circuit, three resistance R_2, R_4\, \, \& \, \, R_3 are parallel.

\frac{1}{R}=\frac{1}{R_2}+\frac{1}{R_4}+\frac{1}{R_3}

=\frac{1}{50}+\frac{1}{50}+\frac{1}{75}

=\frac{75+75+50}{50 \times 75}

R=\frac{50 \times 75}{75+75+50}=\frac{50 \times 75}{200}=\frac{75}{4} \Omega=18.75 \Omega

This resistance is in series with R_1

\therefore R_{\text {resultant }}=R_1+R=100+18.75=118.75 \Omega

Posted by

Sayak

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Latest Question