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In the circuit shown
$\begin{aligned} & \mathrm{R}_1=10 \, \mathrm{ohm} \\ & \mathrm{R}_2=20 \, \mathrm{ohm} \\ & \mathrm{R}_3=30\, \mathrm{ohm} \end{aligned}$
And the potentials of points $\mathrm{A}, \mathrm{B}$ and $\mathrm{C}$ are $10 \mathrm{~V}, 6 \mathrm{~V}$ and $5 \mathrm{~V}$ respectively.

The current though resistance $R_1$ is
Option: 1
0.1A

Option: 2
0.2A

Option: 3
0.3A

Option: 4
0.4A

Answers (1)

best_answer

Let current through $R_1$ is $I_1$

and current through $R_2$ is $I_2$

and current through $R_3$ is $I_1 - I_2$

$10 \ I_1+20 I_2=10-6=4$ $...(1)$

$10 I_1+30\left(I_1-I_2\right)=5$

or $40 I_1 -30 I_2=5$ $...(2)$

Solving for $I_1$ ,

We get $I_1=0.2 \mathrm{~A}$

Posted by

Ritika Kankaria

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