In the circuit shown, switch is closed first and is kept closed for a long time. Now
is closed. Just after that instant the current through
is:
zero
charging of capacitor -
-
just before is closed the potential difference across capacitor 2 is 2E.
just after is closed the potential difference across capacitors 1 and 2 are 0 and 2E respectively. Applying KVL to loop ABCD immediately after
is closed.
E = – iR1 + 0 + 2E
or i = towards left
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