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In the co-axial system of circle \mathrm{x^2+y^2+2 g x+c=0} where g is a parameter, if \mathrm{c>0}. Then the circles are

Option: 1

Orthogonal


Option: 2

Touching type


Option: 3

Intersecting type


Option: 4

Non intersecting type

 


Answers (1)

best_answer

The equation of a system of circle with its centre on the axis of x is \mathrm{x^2+y^2+2 g x+c=0}. Any point on the radical axis

is \mathrm{ \left(0, y_1\right)}

Putting, \mathrm{x=0, y= \pm \sqrt{-c}}

If c is positive \mathrm{(c>0),} we have no real point on radical axis, then circles are said to be non-intersecting type.

Posted by

manish painkra

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