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In the commercial preparation of aluminium, aluminium oxide $\left(\mathrm{Al}_2 \mathrm{O}_3\right)$ is electrolysed at $1000^{\circ} \mathrm{C}$ . Now many coulombs of electricity are required to give 57kg of aluminium?

$\mathrm{\mathrm{Al}^{3+}+3 e^{-} \rightarrow \mathrm{Al}}$ { Rxm takes place at cathode}.
Option: 1
$6.1 \times 10^5 \\$

Option: 2
$3.4 \times 10^2 \\$

Option: 3
$6.1 \times 10^8$

Option: 4
$1.1 \times 10^7$

Answers (1)

best_answer

$\mathrm{57 \times 10^3=\frac{27}{3} \times \frac{x}{96500} }$

$\mathrm{\frac{57 \times 3 \times 96500}{27}=x }$

$\mathrm{x=6.1 \times 10^5 }$

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shivangi.bhatnagar

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