In the expansion of , the constant term is
tr + 1 = (–1)r 15Cr(x3)15 –r = (–1)r 15Cr x45 –3r –2r
For term independent of x 45 –5r = 0 ⇒ r = 9
∴ term independent of x will be = –15C9 = –15C6
Hence (B) is the correct answer.
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