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In the expansion of \left(2 x^2-\frac{1}{x}\right)^{12}, the term independent of x  is 

Option: 1

10^{\text {th }}


Option: 2

9^{\text {th }}


Option: 3

8^{\text {th }}


Option: 4

7^{\text {th }}


Answers (1)

best_answer

T_{r+1}={ }^{12} C_r\left(2 x^2\right)^{12-r}(-1)\left(\frac{1}{x}\right)^r

For term independent of x,  24-3 r=0 \Rightarrow r=8.

So, 9th  term independent of x.    

Posted by

Divya Prakash Singh

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