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In the figure is shown Young's double slit experiment. Q is the position of the first bright fringe on the right side of \mathrm{O . P} is the \mathrm{11^{\text {th }}} fringe on the other side, as measured from Q. If the wavelength of the light used is \mathrm{6000 \times 10^{-10} \mathrm{~m},} then \mathrm{S_1 B} will be equal to

Option: 1

\mathrm{6 \times 10^{-6} \mathrm{~m}}


Option: 2

\mathrm{6.6 \times 10^{-6} \mathrm{~m}}


Option: 3

\mathrm{3.138 \times 10^{-7} \mathrm{~m}}


Option: 4

\mathrm{3.144 \times 10^{-7} \mathrm{~m}}


Answers (1)

best_answer

P is the position of \mathrm{11^{\text {th }}} bright fringe from Q. From central position O,P will be the position of \mathrm{10^{\text {th }}} bright fringe.

Path difference between the waves reaching at \mathrm{P=S_1 B=10 \lambda=10 \times 6000 \times 10^{-10} =6 \times 10^{-6} \mathrm{~m}.}

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Divya Prakash Singh

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