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In the figure shown the acceleration of A is \vec{a}_{A}=15i+ 15j  

then the acceleration of B is: (A remains in contact with B) 

                         

                                       

 

 

 

                     

Option: 1

6\: \hat{i}


Option: 2

-15\; \hat{i}        


Option: 3

-10\; \hat{i}


Option: 4

-5\; \hat{i}


Answers (1)

best_answer

 

When an Inclined Plane is given -

- wherein

R=mg\:cos\theta along normal to the incline

mg\:sin\theta =ma along the incline

a=g\:sin\theta

 

 a_{Ay}cos53-a_{B}cos37=a_{B}cos53\\a_B=-5im/s^2

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rishi.raj

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