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In the following circuit diagram inductive reactance of inductor is 24 \Omega and capacitive reactance of capacitor is 48 \Omega, then reading of ammeter will be

Option: 1

5 A


Option: 2

2.4 A


Option: 3

2.0 A


Option: 4

10 A


Answers (1)

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\mathrm{\begin{aligned} & \mathrm{i}_{\mathrm{L}}=\frac{240}{24}=10 \mathrm{~A} \\ & \mathrm{i}_{\mathrm{C}}=\frac{240}{48}=5 \mathrm{~A} \end{aligned}}

\mathrm{\text { Hence } \mathrm{i}=\mathrm{i}_{\mathrm{L}}-\mathrm{i}_{\mathrm{C}}=5 \mathrm{~A}}

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