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  • In the following common emitter configuration an N P N transistor with current gain  is used. The

In the following common emitter configuration an N P N transistor with current gain \beta= 100 is used. The output voltage of the amplifier will be

Option: 1

10 \mathrm{mV}


Option: 2

0.1 \mathrm{V}


Option: 3

1.0 \mathrm{V}


Option: 4

10 \mathrm{V}


Answers (1)

best_answer

\mathrm{\begin{aligned} & \text { Voltage gain }=\frac{\text { Output voltage }}{\text { Input voltage }} \\ & \Rightarrow V_{\text {out }}=V_{\text {in }} \times \text { Voltage gain } \\ & \Rightarrow V_{\text {out }}=V_{\text {in }} \times \text { Current gain } \times \text { Resistance gain } \\ & =V_{\text {in }} \times \beta \times \frac{R_L}{R_{B E}}=10^{-3} \times 100 \times \frac{10}{1}=1 \mathrm{~V} \end{aligned} }

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Ajit Kumar Dubey

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