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  • In the Freundlich adsorption isotherm,<img alt="\mathrm{\log \left(\frac{x}{m}\right)=\log k+\frac{1}{n} \log p}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7B%5Clog%20%5Cleft%2

In the Freundlich adsorption isotherm,\mathrm{\log \left(\frac{x}{m}\right)=\log k+\frac{1}{n} \log p} , the value of \mathrm{n} is:

Option: 1

any value from 0 to 1.


Option: 2

A positive integer.


Option: 3

A negative integer.


Option: 4

A positive or negative fractional number.


Answers (1)

best_answer

By Freundlich Adsorption Isotherm,

\mathrm{\log \left(\frac{x}{m}\right)=\log k+\frac{1}{n} \log P}
\mathrm{\frac{x}{m}} is the extent of adsorption which means the amount of gas adsorbed by the adsorbent with pressure at constant temperature.
\mathrm{k} and \mathrm{n} are constants that depends on the nature of gas and adsorbent.

In Freundlich Adsorption Isotherm,

At low temperature, the isotherm is a straight line.
\mathrm{\therefore \frac{1}{n}=1}
\mathrm{\Rightarrow \frac{x}{m}=k p}
At intermediate pressure,
\mathrm{0<\frac{1}{n}<1}
Hence,
\mathrm{\Rightarrow \frac{x}{m}=k p^{\frac{1}{n}}}
At high pressure, the extent of adsorption attains a constant value and becomes independent of pressure. Thus,\mathrm{\frac{1}{n}=0}
\mathrm{\Rightarrow \frac{x}{m}=k}
Hence,
The value of \mathrm{1 / \mathrm{n}}  lies between 0 to 1 under different pressure ranges.

So the value of \mathrm{ \mathrm{'n'}}cannot be a negative integer or a fractional number. 
It can only be a positive integer.

Posted by

Irshad Anwar

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