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  • In the given circuit diagram, a wire is joining points B and D. The current in this wire is: (current in amperes,A)  <img alt="" src="https://cdn.entrance360.com/media/uploads/2020/01/16/screenshot-from-2020-01-16-23-53-57.png" style="height:130px

In the given circuit diagram, a wire is joining points B and D. The current in this wire is: (current in amperes,A) 
Option: 1 2
Option: 2 0
Option: 3 0.4
Option: 4 4
 

Answers (1)

best_answer

 

 

 

 

 

\\ \text{Reff} = \frac{4}{5} +\frac{6}{5} = 2\Omega \\ i = \frac{20}{2} = 10A

 

So after drawing the circuit 

 

 

I = \frac{4i}{5} - \frac{3i}{5} = +\frac{i}{5} = 2A

Hence the option correct option is (1).

Posted by

avinash.dongre

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