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In the given circuit

The current through the battery is:

 

Option: 1

0.5 A


Option: 2

1 A


Option: 3

1.5 A


Option: 4

2 A


Answers (1)

best_answer

In the given circuit, diode \mathrm{D_{1}} is reverse biased, so it will not conduct. Diodes \mathrm{D_{2}} and \mathrm{D_{3}} are forward biased,

so they will conduct. The corresponding equivalent circuit is a shown in the figure.

The equivalent resistnce of the circuit is

\mathrm{R_{e q}=\frac{(5+5) \times 20}{(5+5)+20}=\frac{10 \times 20}{10+20}=\frac{200}{30}=\frac{20}{3} \Omega}

Current through the battery, \mathrm{\mathrm{I}=\frac{10 \mathrm{~V}}{\frac{20}{3} \Omega}=1.5 \mathrm{~A}}

 

Posted by

Rishabh

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