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In the given circuit the input voltage V in is shown in figure. The cut- in voltage of p-n junction diode \mathrm{\left(D_{1} \text { or } D_{2}\right)} is \mathrm{0.6 \mathrm{~V}}. Which of the following output voltage \mathrm{\left(\mathrm{V}_{\mathrm{o}}\right)} waveform across the diode is correct ?  

 

Option: 1


Option: 2


Option: 3


Option: 4


Answers (1)

best_answer

In +ve half cycle
\mathrm{D}_{1} \rightarrow F.B.; \quad \mathrm{D}_{2} \rightarrow R.B. 
In -ve half cycle
\mathrm{D}_{2} \rightarrow F.B.; \quad \mathrm{D}_{1} \rightarrow R.B.

So in both the cycles one of the diode will be in forward biased.

 For \ \ |\mathrm{V}_{in}| \leq 0.6 \mathrm{~V},|\mathrm{Vo}|=\mathrm{V}_{in}

For \ \ |\mathrm{V}_{in}| > 0.6 \mathrm{~V},|\mathrm{Vo}|= 0.6 \ V

so the correct graph will be  


Hence D is correct option.

Posted by

chirag

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