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In the given circuit voltage across \text{R}_{4} is :

Option: 1

0.4 V


Option: 2

0.6 V


Option: 3

0.8 V


Option: 4

1.0 V


Answers (1)

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Here \left(\mathrm{R}_3\right) 60 \Omega \text { and }\left(\mathrm{R}_4\right) 30 \Omega are in parallel. Their combination is in series with \left(\mathrm{R}_5\right) 30 \Omega resistance. Their effective resistance is =\frac{60 \times 30}{60+30}+30 \Omega=20+30=50 \Omega

It is in parallel with resistance \left(\mathrm{R}_2\right) 50 \Omega with together is in series with \left(\mathrm{R}_1\right) 50 \Omega . The effective resistance of the circuit is =50+\frac{50 \times 50}{50+50}=50+25=75 \Omega

Current in the circuit is \mathrm{I}=\frac{3 \mathrm{~V}}{75 \Omega}=\frac{1}{25} \mathrm{~A}

Current through \mathrm{R}_5=\frac{1}{2} \times \frac{1}{25}=\frac{1}{50} \mathrm{~A}

Current through \mathrm{R}_4=\frac{2}{3} \times \frac{1}{50}=\frac{1}{75} \mathrm{~A}

Potential difference across \mathrm{R}_4=30 \times \frac{1}{75}=0.4 \mathrm{~V}

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rishi.raj

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