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In the given potentiometer circuit length of the wire \mathrm{A B} is \mathrm{3 \mathrm{~m}} and resistance is \mathrm{R=4.5 \Omega}. The length \mathrm{A C} for no deflection in galvanometer is

Option: 1

\mathrm{2\, m}


Option: 2

1.8 \mathrm{~m}


Option: 3

 dependent on \mathrm{r_{1}}


Option: 4

None of these


Answers (1)

best_answer

Let \mathrm{l} is the length of potentiometer.

\mathrm{i=\frac{5 \mathrm{~V}}{5 \Omega}=1 \mathrm{~A} }.

For no deflection current through Galvanometer is zero.

\mathrm{\Rightarrow P \cdot D \text { across } A B=4.5 \times i=4.5 \mathrm{~V} }
\mathrm{V_{A C}=3 \mathrm{~V} \Rightarrow\left(\frac{4.5}{3}\right) l \times I=3 \mathrm{~V} }

\mathrm{\Rightarrow \quad 1.5 \times l \times 1=3 }
\mathrm{\Rightarrow l=2 m }.

Posted by

Ritika Harsh

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