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  • In the lead storage battery, the anode reaction is <img alt="\mathrm{Pb}(\mathrm{s})+\mathrm{HSO}_4^{-}+\mathrm{H}_2 \mathrm{O} \rightarrow \mathrm{PbSO}_4(\mathrm{s})+\mathrm{H}_3 \mathrm{O}^{+}+2

In the lead storage battery, the anode reaction is \mathrm{Pb}(\mathrm{s})+\mathrm{HSO}_4^{-}+\mathrm{H}_2 \mathrm{O} \rightarrow \mathrm{PbSO}_4(\mathrm{s})+\mathrm{H}_3 \mathrm{O}^{+}+2 \mathrm{e}^{-} How many grams of Pb will be used up to deliver 2A for 150h ?

Option: 1

382 gm


Option: 2

480 gm


Option: 3

232 gm


Option: 4

581 gm


Answers (1)

best_answer

\mathrm{ n_{e q}=\frac{Q}{F} }

\mathrm{ \frac{\omega}{208} \times 2=\frac{2 \times 150 \times 3600}{96500}}

\mathrm{ 2 \omega =\frac{2 \times 150 \times 3600 \times 208}{96500} \\ }

\mathrm{ \omega =\frac{2 \times 150 \times 3600 \times 208}{96500 \times 2} \\ }

\mathrm{ \frac{\omega}{2} =581 \mathrm{~gm} }

Posted by

Devendra Khairwa

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