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  • In the shown diagram, threeridentical containers holds methane,<img alt="\mathrm{ \mathrm{O}_2 ~and ~\mathrm{SO}_2}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7B%20%5Cmathrm%7B

In the shown diagram, threeridentical containers holds methane,\mathrm{ \mathrm{O}_2 ~and ~\mathrm{SO}_2} in the mass ratio of 4: 2: 1 respectively, but at the same temperature. The pressures exerted by \mathrm{CH}_4: \mathrm{O}_2: \mathrm{SO}_2 are is the ratio of -

Option: 1

1: 1: 1


Option: 2

16: 4: 1
 


Option: 3

1: 4: 16


Option: 4

32: 8: 1


Answers (1)

best_answer

use idea has equation,
\begin{aligned} &\mathrm{ P V=n R T }\\ &\mathrm{ p \propto n }\\ &\mathrm{ P_{\mathrm{CH}_4}: P_{\mathrm{O}_2}: P_{\mathrm{SO}_4} }\\ &\mathrm{ n_{\mathrm{CH}_4}: n_{\mathrm{O}_2}: n_{\mathrm{SO}_4} }\\ &\mathrm{ =\frac{\text { mass } \mathrm{CH}_4}{\text { moran Mass } \mathrm{CH}_4}: \frac{\text { mass } \mathrm{O}_2}{\text { nolan man Or }}: \frac{\text { mass } \mathrm{sO}_4}{\text { molars man soy }} }\\ &\mathrm{ =\frac{4}{16}: \frac{2}{32}: \frac{1}{64} }\\ &\mathrm{ =16: 4: 1 }\\ \end{aligned}
option (b) correct.

Posted by

Deependra Verma

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