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  • In the shown network the energy stored in the inductor in steady state will be <img alt="" src="https://cdn.entrance360.com/media/uploads/2023/08/18/191812.jpg" style="height:147px; width

In the shown network the energy stored in the inductor in steady state will be

Option: 1

Zero


Option: 2

\mathrm{\frac{L E^2}{2 R^2}}


Option: 3

\mathrm{\frac{L E^2}{ R^2}}


Option: 4

\mathrm{\frac{2L E^2}{ R}}


Answers (1)

best_answer

Since capacitor offers infinite resistance & inductor offers zero resistance to DC at
steady state, current through battery in steady state
=\mathrm{\frac{E}{(R / 2)}=\frac{2 E}{R}}
and current through inductor =\mathrm{\varepsilon / R}
Hence, energy stored =\mathrm{ \frac{1}{2} L\left(\frac{E}{R}\right)^2=\frac{L^2}{2 R^2}}

Posted by

Devendra Khairwa

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