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  • In the sulphur estimation, 0.471 g of an organic compound gave 1.44 g of barium sulfate. The percentage of sulphur in the compound is  _______ % .(Nearest integer) (Atomic mass of Ba = 137 u)Option: 1 42Option: 2 --

In the sulphur estimation, 0.471 g of an organic compound gave 1.44 g of barium sulfate. The percentage of sulphur in the compound is  _______ % .(Nearest integer) (Atomic mass of Ba = 137 u)
 

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best_answer

Molar mass of BaSO4 = 233 g

\mathrm{\therefore moles\: of\: BaSO_{4}= \frac{1. 44}{233} = moles\ of\ S}

\mathrm{\therefore mass\: of\: S\, present= \frac{1. 44}{233}\times 32} 

\mathrm{\therefore % \,S = \frac{1. 44\times 32 }{233\times 0. 471}\times 100 = 41.98%}

Hence, the correct answer is 42

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sudhir.kumar

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