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In this figure the resistance of the coil of galvanometer G is 2 \Omega . The emf of the cell is 4 V. The ratio of potential difference across C1 and C2 is:

Option: 1

\frac{5}{4}


Option: 2

1


Option: 3

\frac{4}{5}


Option: 4

\frac{3}{4}


Answers (1)

best_answer

At steady state current will not be in the capacitor branch.
\begin{aligned} & i=\frac{4}{6+2+8} \\ & \mathrm{i}=\frac{1}{4} \mathrm{~A} \\ & \Delta \mathrm{V}_{\mathrm{C}_1}=\mathrm{i}(6+2) \\ & \Delta \mathrm{V}_{\mathrm{C}_2}=\mathrm{i}(2+8) \\ & \frac{\Delta V_{\mathrm{C}_1}}{\Delta \mathrm{V}_{\mathrm{C}_2}}=\frac{4}{5} \\ & \end{aligned}         

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Divya Prakash Singh

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