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In triangle PQR, p,q,r are in G.P. and \angle Q=60^{\circ}. Then  p^2,q^2,r^2 are in ?

Option: 1

A.P.


Option: 2

G.P.


Option: 3

H.P.


Option: 4

None of these


Answers (1)

best_answer

\\p,q,r \ are\ in\ G.P. \Rightarrow q^2=pr\\\\ \cos Q=\frac{1}{2}=\frac{p^2+r^2-q^2}{2pr}\\ p^2+r^2-q^2=pr\\ p^2+r^2=2q^2\\ p^2,q^2,r^2 \ are\ in\ A.P.

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Devendra Khairwa

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