Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • In Young's double slit experiment using a monochromatic light of wavelength , the path difference (in terms

In Young's double slit experiment using a monochromatic light of wavelength \lambda , the path difference (in terms of integer) corresponding to any point having half of peak intensity is
 

Option: 1

\left ( 2n+1 \right )\frac{\lambda }{2}


Option: 2

\left ( 2n+1 \right )\frac{\lambda }{4}


Option: 3

\left ( 2n+1 \right )\frac{\lambda }{8}

 


Option: 4

\left ( 2n+1 \right )\frac{\lambda }{16}


Answers (1)

best_answer

Answer (2)
I=I_{max}\cos ^2\left ( \frac{\phi }{2} \right )\\\frac{1}{2}=\cos ^2\left ( \frac{\phi }{2} \right )\\\Delta x=\left ( 2n+1 \right )\frac{\lambda }{4}

Posted by

Gaurav

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025: NIT Rourkela cut-offs for CSE, chemical engineering drop; last years' closing ranks
anam-khan

JEE Main 2025 Live: NTA exam city slip at jeemain.nta.nic.in soon; session 1 schedule
anam-khan

JEE Main 2025 schedule out for session 1; paper 1 from January 22

Latest Question