Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

\sum_{\mathrm{k}=0}^6{ }^{51} \mathrm{C}_3 is equal to

Option: 1

{ }^{51} \mathrm{C}_4-{ }^{45} \mathrm{C}_4


Option: 2

{ }^{52} \mathrm{C}_3-{ }^{45} \mathrm{C}_3


Option: 3

{ }^{52} \mathrm{C}_4-{ }^{45} \mathrm{C}_4


Option: 4

{ }^{51} \mathrm{C}_3-{ }^{45} \mathrm{C}_3


Answers (1)

best_answer

{ }^{51} \mathrm{C}_3+{ }^{50} \mathrm{C}_3+{ }^{49} \mathrm{C}_3+{ }^{48} \mathrm{C}_3+{ }^{47} \mathrm{C}_3+{ }^{46} \mathrm{C}_3+{ }^{45} \mathrm{C}_3

add and subtract { }^{45} \mathrm{C}_4

\begin{aligned} & \left({ }^{45} \mathrm{C}_4+{ }^{45} \mathrm{C}_3\right)+{ }^{46} \mathrm{C}_3+{ }^{47} \mathrm{C}_3+{ }^{48} \mathrm{C}_3+{ }^{49} \mathrm{C}_3+{ }^{50} \mathrm{C}_3+{ }^{51} \mathrm{C}_3-{ }^{45} \mathrm{C}_4 \quad\left({ }^{\mathrm{n}} \mathrm{C}_{\mathrm{r}}+{ }^{\mathrm{n}} \mathrm{C}_{\mathrm{r}-1}={ }^{\mathrm{n}+1} \mathrm{C}_{\mathrm{r}}\right) \\ & { }^{52} \mathrm{C}_4-{ }^{45} \mathrm{C}_4 \\ & \Rightarrow[\mathrm{C}] \end{aligned}

Posted by

Anam Khan

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

NTA JEE Mains 2027 application form filling starts soon; January BTech, BE entrance exam dates
anam-khan

Supreme Court appointed task force finds 9% students experience suicidal thoughts
anam-khan

JEE Main 2027 exam dates out; session 1 from January 22

Latest Question