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Let \mathrm{A=\{2,3,4, \ldots, 20,21\}}. A number is chosen at random from the set $A$ and it is found to be a prime number. The probability that it is more than 10 is

Option: 1

\frac{9}{10}


Option: 2

\frac{1}{10}


Option: 3

\frac{1}{5}


Option: 4

None of these


Answers (1)

best_answer

The required probability = (probability of drawing a prime number) X (Probability of the second being faulty when the first is faulty)

=\frac{8}{20} \times \frac{4}{8}=\frac{1}{5}
 

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