Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Let C be the curve which is the locus of the point of intersection of lines and <i

Let C be the curve which is the locus of the point of intersection of lines \mathrm{x=2+m} and \mathrm{m y=4-m}. A circle \mathrm{s=(x-2)^2+(y+1)^2 =25} intersects the curve C at four points : P, Q, R and S. If O is centre of the curve C, then O \mathrm{P^2+O Q^2+O R^2+O S^2} is

Option: 1

100


Option: 2

155


Option: 3

129


Option: 4

147


Answers (1)

best_answer



\begin{aligned} &\mathrm{x-2=m}\\ &\mathrm{y+1=\frac{4}{m} }\\ &\mathrm{\therefore \quad(x-2)(y+1)=4}\\ &\mathrm{or ~X Y=4}\\ &\mathrm{where~ X=(x-2), Y=(y+1)}\\ &\mathrm{s=(x-2)^2+(y+1)^2=25}\\ &\mathrm{or ~X^2+Y^2=25}\\ &\text{Curve C and circle S both are concentric. Therefore,}\\ &\mathrm{ O P^2+O Q^2+O R^2+O S^2=4 r^2 }\\ &\mathrm{ \quad=4 \times 25=100} \end{aligned}

Posted by

manish painkra

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

How to crack JEE Mains 2025 in 1 month? Follow study plan, revise high-score topics, experts advice
anam-khan

IIT JEE aspirant from Bihar found hanging in Kota hostel; 17th suicide this year
anam-khan

JEE Main 2025 just a month away; section-wise preparation tips, important topics, strategies

Latest Question