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Let the abscissae of the two points \mathrm{\mathrm{P}} and \mathrm{\mathrm{Q}} on a circle be the roots of \mathrm{x^{2}-4 x-6=0} and the ordinates of \mathrm{P} and \mathrm{Q} be the roots of \mathrm{y^{2}+2 y-7=0}. If \mathrm{PQ} is a diameter of the circle \mathrm{x^{2}+y^{2}+2 a x+2 b y+c=0}, then the value of \mathrm{(a+b-c)} is _____________.

Option: 1

12


Option: 2

13


Option: 3

14


Option: 4

16


Answers (1)

best_answer

Equation of circle with PQ as diameter is

\mathrm{x^{2}-4 x-6+y^{2}+2 y-7=0} \\

\mathrm{\Rightarrow x^{2}+y^{2}-4 x+2 y-13=0} \\

\mathrm{\therefore a=-2, b=1, c=-13} \\

\mathrm{\therefore a+b-c=12}

Hence correct option is 1

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Ritika Jonwal

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