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Let the function $f(x)=2 x^3+(2 p-7) x^2+3(2 p-9) x-6$ have a maxima for some value of $x<0$ and a minima for some value of $x>0$ . Then, the set of all values of $p$ is
Option: 1
$\left(0, \frac{9}{2}\right)$

Option: 2
$\left(-\infty, \frac{9}{2}\right)$

Option: 3
$\left(-\frac{9}{2}, \frac{9}{2}\right)$

Option: 4
$\left(\frac{9}{2}, \infty\right)$

Answers (1)

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HARSH KANKARIA

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