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  • Let the mean of 6 observations 1, 2, 4, 5 5 and their variance be 10. Then their mean deviati

Let the mean of 6 observations 1, 2, 4, 5 x\: and\; y 5 and their variance be 10. Then their mean deviation about the mean is equal to

Option: 1

\frac{7}{3}


Option: 2

\frac{10}{3}


Option: 3

\frac{8}{3}


Option: 4

3


Answers (1)

best_answer

Mean of 1, 2, 4, 5, x, y is 5
and variance is 10

\Rightarrow$ mean $\Rightarrow \frac{12+\mathrm{x}+\mathrm{y}}{6}=5
12+x+y=30
x+y=18

\text{and by variance }= \frac{x^{2}+y^{2}+46}{6}-5^{2}=10
\mathrm{x}^{2}+\mathrm{y}^{2}=164
x=8 \quad y=10

\text{mean daviation}=\frac{|\mathrm{x}-\overline{\mathrm{x}}|}{6}
\Rightarrow \frac{4+3+1+0+3+5}{6}=\frac{16}{6}=\frac{8}{3}

Posted by

Devendra Khairwa

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