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  • Let the vertices of a triangle be and <img alt="(2,0)" src="https://entrancecorner.oncodeco

Let the vertices of a triangle be (0,0),(0,2) and (2,0). The distance between its orthcentre and circumcentre is

Option: 1

0


Option: 2

1 / \sqrt{2}


Option: 3

\sqrt{2}


Option: 4

none of these


Answers (1)

best_answer

\mathrm{A(0,0), B(2,0)} and \mathrm{C(0,2)} form a right angled triangle, right angle at \mathrm{A(0,0)} and \mathrm{B C} hypotenuse.

So  \mathrm{A(0,0)} is orthocentre and mid-point \mathrm{D} of \mathrm{BC} i.e.\mathrm{(1,1)} is circumcentre.

\therefore    distance between circumcentre and orthocentre \mathrm{=A D=\sqrt{2}}.

Posted by

shivangi.bhatnagar

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