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  • Magnetic field at the centre of a current carrying circular loop of area A is B. Then magnetic moment of the loop will be:Option: 1 <img alt="\frac{\

Magnetic field at the centre of a current carrying circular loop of area A is B. Then magnetic moment of the loop will be:

Option: 1

\frac{\mathrm{BA}^2}{\mu_0 \pi}


Option: 2

\frac{\mathrm{BA}}{\mu_0} \sqrt{\mathrm{A}}


Option: 3

\frac{\mathrm{BA} \sqrt{\mathrm{A}}}{\mu_0 \pi}


Option: 4

\frac{2 \mathrm{BA}}{\mu_0} \sqrt{\frac{\mathrm{A}}{\pi}}


Answers (1)

best_answer

\begin{array}{lr} \mathrm{B}=\frac{\mu_0 \mathrm{I}}{2 \mathrm{R}}, & \mathrm{A}=\pi \mathrm{R}^2 \\ \mathrm{IA}=\frac{2 \mathrm{BR}}{\mu_0} & \mathrm{~A}=\frac{2 \mathrm{~B}}{\mu_0} \sqrt{\frac{\mathrm{A}}{\pi}} \mathrm{A} \end{array}

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