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Manganese (VI) has ability to disproportionate in acidic solution. The difference in oxidation states of two ions it forms in acidic solution is_________.

Option: 1

3


Option: 2

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Option: 3

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Option: 4

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Answers (1)

best_answer

Manganese (VI) is not stable in acidic medium and undergoes disproportionation reaction.

The reaction is given below:

\\\mathrm{3MnO_{4}^{2-}+4H^{+}\longrightarrow 2MnO_{4}^{-}+MnO_{2}+2H_{2}O}\\\mathrm{(VI)}\; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \mathrm{(VII)}\; \; \; \; \; \; \; \mathrm{(IV)}

The difference in oxidation state of two lons

=7-4=3

Hence, the answer is 3

Posted by

rishi.raj

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