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Match List - I with List - II.

List - I

List - II

(A) Concentration of gold ore

(I) Aniline

(B) Leaching of alumina

 (II)\mathrm{NaOH}

(C) Froth stabiliser

 (III)\mathrm{SO}_{2}

(D) Blister copper

 (IV)\mathrm{NaCN}

Choose the correct answer from the options given below.

Option: 1

(\mathrm{A})-(\mathrm{IV}),(\mathrm{B})-(\mathrm{III}),(\mathrm{C})-(\mathrm{II}),(\mathrm{D})-(\mathrm{I})


Option: 2

(\mathrm{A})-(\mathrm{IV}),(\mathrm{B})-(\mathrm{II}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{III})


Option: 3

(\mathrm{A})-(\mathrm{III}),(\mathrm{B})-(\mathrm{II}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{IV})


Option: 4

(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{IV}),(\mathrm{C})-(\mathrm{III}),(\mathrm{D})-(\mathrm{I})


Answers (1)

best_answer

(A) NaCN is used for concentration of Gold ore. (IV)
(B) Leaching of alumina is done by \mathrm{NaOH} (II)
(C) Foth stabiliser \rightarrow Aniline (I)
(D) Blister copper \rightarrow due to the evolution of \mathrm{SO}_{2} (III)

Hence, the correct answer is Option (2)

Posted by

Rishabh

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